Solve the following system of linear inequalities graphically:
$x+y \geq 5$ ..... $(1)$
$x-y \leq 3$ ..... $(2)$

(N/A) The graph of the linear equation $x+y=5$ is drawn.
Inequality $(1)$ is represented by the shaded region above the line $x+y=5$,including the points on the line.
On the same set of axes,we draw the graph of the equation $x-y=3$. Then we note that inequality $(2)$ represents the shaded region above the line $x-y=3$,including the points on the line.
Clearly,the double shaded region,common to the above two shaded regions,is the required solution region of the given system of inequalities.