Solve the given inequality graphically in a two-dimensional plane: $x+y < 5$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The graphical representation of $x+y=5$ is given as a dotted line in the figure below.
This line divides the $xy$-plane into two half-planes,$I$ and $II$.
Select a point (not on the line),which lies in one of the half-planes,to determine whether the point satisfies the given inequality or not.
We select the point as $(0,0)$.
It is observed that,
$0+0 < 5$ or $0 < 5$,which is true.
Therefore,the half-plane $I$ is the solution region of the given inequality.
Also,it is evident that any point on the line does not satisfy the given strict inequality.
Thus,the solution region of the given inequality is the shaded half-plane $I$ excluding the points on the line.

Explore More

Similar Questions

Solve $y < 2$ graphically.

Solve the given inequality for real $x: 3(2-x) \geq 2(1-x)$

Solve the given inequality graphically in a two-dimensional plane: $x-y \leq 2$

The solution set of $x < 5$ and $x \geq 2$ is...

Solve the inequality $2 \leq 3x - 4 \leq 5$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo