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(D) For equation $I: x^{2}-19x+84=0$We need two numbers whose product is $84$ and sum is $19$. These numbers are $12$ and $7$.$x^{2}-12x-7x+84=0$$x(x-

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(D) For equation $I: x^{2}-19x+84=0$We need two numbers whose product is $84$ and sum is $19$. These numbers are $12$ and $7$.$x^{2}-12x-7x+84=0$$x(x-12)-7(x-12)=0$$(x-12)(x-7)=0$So,$x = 12$ or $x = 7$.For equation $II: y^{2}-25y+156=0$We need two numbers whose product is $156$ and sum is $25$. These numbers are $13$ and $12$.$y^{2}-13y-12y+156=0$$y(y-13)-12(y-13)=0$$(y-13)(y-12)=0$So,$y = 13$ or $y = 12$.Comparing the values:If $x=12$,then $y=13$ $(x If $x=7$,then $y=13$ $(x In all cases,$x \le y$.

Solve the given two equations and select the correct answer from the given options.
$I. x^{2}-19x+84=0$
$II. y^{2}-25y+156=0$

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Solve the given two equations and select the correct answer from the given options.$I. x^{2}-19x+84=0$$II. y^{2}-25y+156=0$