Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2}-24x+144=0$
$II.$ $y^{2}-26y+169=0$

  • A
    If $x < y$
  • B
    If $x > y$
  • C
    If $x = y$
  • D
    If $x \geq y$

Explore More

Similar Questions

The expression $x^2 + 2bx + c$ has a positive value for all real $x$ if:

Product of real roots of the equation ${t^2}{x^2} + |x| + 9 = 0$.

The set of values of $x$ which satisfy $5x + 2 < 3x + 8$ and $\frac{x + 2}{x - 1} < 4$ is:

If $\left\{\frac{1}{2}(a-b)\right\}^{2}+a b=p(a+b)^{2},$ then the value of $p$ is (assume that $a \neq-b).$

Solve the given two equations and select the correct answer from the given options.
$I.$ $x = \sqrt{2304}$
$II.$ $y^2 = 2304$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo