Split 207 into three parts such that these ar | vedclass

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(A) Let the three parts of the number $207$ be $(a - d)$,$a$,and $(a + d)$,which are in $AP$.According to the given condition:Sum of these parts $= 20

Vedclass · Accepted Answer

$67, 69, 71$

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(A) Let the three parts of the number $207$ be $(a - d)$,$a$,and $(a + d)$,which are in $AP$.According to the given condition:Sum of these parts $= 207$$(a - d) + a + (a + d) = 207$$3a = 207$$a = 69$Given that the product of the two smaller parts is $4623$:$a(a - d) = 4623$$69(69 - d) = 4623$$69 - d = \frac{4623}{69}$$69 - d = 67$$d = 69 - 67 = 2$Therefore,the three parts are:First part $= a - d = 69 - 2 = 67$Second part $= a = 69$Third part $= a + d = 69 + 2 = 71$Thus,the required three parts are $67, 69, 71$.

Split $207$ into three parts such that these are in $AP$ and the product of the two smaller parts is $4623$.

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