Strong reducing behaviour of $H_3PO_2$ is due to

  • A
    High oxidation state of phosphorus
  • B
    Presence of two $-OH$ groups and one $P-H$ bond
  • C
    Presence of one $-OH$ group and two $P-H$ bonds
  • D
    High electron gain enthalpy of phosphorus

Explore More

Similar Questions

When copper metal is treated with cold and dilute nitric acid, it forms

Nitrogen forms how many oxides?

$(NH_4)_2Cr_2O_7$ on heating gives:

The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are

Given below are the two statements: one is labeled as Assertion $(A)$ and the other is labeled as Reason $(R)$.
Assertion $(A)$: There is a considerable increase in covalent radius from $N$ to $P$. However,from $As$ to $Bi$,only a small increase in covalent radius is observed.
Reason $(R)$: Covalent and ionic radii in a particular oxidation state increase down the group.
In the light of the above statements,choose the most appropriate answer from the options given below:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo