Structure of IF_6^- is : | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the structure of $IF_6^-$,we calculate the number of electron pairs around the central iodine atom $(I)$.The central atom $I$ has $7$

Vedclass · Accepted Answer

Distorted octahedral

Vedclass · Answer

(B) To determine the structure of $IF_6^-$,we calculate the number of electron pairs around the central iodine atom $(I)$.The central atom $I$ has $7$ valence electrons.Adding $1$ electron from the negative charge gives $8$ electrons.It forms $6$ bonds with fluorine atoms,using $6$ electrons.This leaves $2$ electrons,which form $1$ lone pair.Total electron pairs = $6$ (bond pairs) + $1$ (lone pair) = $7$ electron pairs.According to $VSEPR$ theory,$7$ electron pairs correspond to a pentagonal bipyramidal electron geometry.With $6$ bond pairs and $1$ lone pair,the molecular geometry is distorted octahedral.

Structure of $IF_6^-$ is :

Similar Questions

The shapes of $SOF_4$,$XeO_2F_2$ and $ClF_3$ are respectively:

Which of the following structures of a molecule is expected to have three bond pairs and one lone pair of electrons?

In a $AX_2L_n$ compound,if $X$ is a bond pair and $n$ is the number of lone pairs of electrons,which of the following options is incorrect?

In order that the diagram below correctly depicts the structure of $ICl_2^-$,at what positions should the $Cl$ atoms be drawn? The central atom is $I$.

Which of the following has the smallest bond angle?

Vedclass Test Series

Exam Paper Generator

Online Exam Module