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(D) The central atom $I$ in $ICl_2^-$ has $7$ valence electrons. It forms $2$ bonds with $Cl$ atoms and has $3$ lone pairs of electrons. According to

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$4, 5$

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(D) The central atom $I$ in $ICl_2^-$ has $7$ valence electrons. It forms $2$ bonds with $Cl$ atoms and has $3$ lone pairs of electrons. According to $VSEPR$ theory,for a trigonal bipyramidal geometry ($sp^3d$ hybridization),the lone pairs occupy the equatorial positions to minimize repulsion. Therefore,the $Cl$ atoms must occupy the axial positions,which correspond to positions $4$ and $5$ in the given diagram.

In order that the diagram below correctly depicts the structure of $ICl_2^-$,at what positions should the $Cl$ atoms be drawn? The central atom is $I$.

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