Which set of species is arranged in order of | vedclass

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(D) To determine the bond angle,we look at the hybridization and the number of lone pairs on the central nitrogen atom:$1$. $NO_2^+$: The nitrogen ato

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$NO_2^-, NO_3^-, NO_2^+$

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(D) To determine the bond angle,we look at the hybridization and the number of lone pairs on the central nitrogen atom:$1$. $NO_2^+$: The nitrogen atom is $sp$ hybridized with $0$ lone pairs,resulting in a linear geometry with a bond angle of $180^{\circ}$.$2$. $NO_3^-$: The nitrogen atom is $sp^2$ hybridized with $0$ lone pairs,resulting in a trigonal planar geometry with a bond angle of $120^{\circ}$.$3$. $NO_2^-$: The nitrogen atom is $sp^2$ hybridized with $1$ lone pair,resulting in a bent geometry. Due to the lone pair-bond pair repulsion,the bond angle is approximately $115^{\circ}$.Comparing these,the order of increasing bond angle is $NO_2^- (115^{\circ}) Thus,the correct sequence is $NO_2^-, NO_3^-, NO_2^+$.

Which set of species is arranged in order of increasing $O-N-O$ bond angle?

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