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(C) The weight of the passenger is the net gravitational force acting on them,given by $F = F_E - F_M$,where $F_E$ is the gravitational force due to E

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$C$

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(C) The weight of the passenger is the net gravitational force acting on them,given by $F = F_E - F_M$,where $F_E$ is the gravitational force due to Earth and $F_M$ is the gravitational force due to Mars.As the spaceship moves from Earth to Mars,the distance from Earth increases and the distance from Mars decreases.Initially,at the Earth's surface,the weight is $W = m 	imes g_E = 60 	imes 10 = 600\, N$.As the spaceship moves away from Earth,the gravitational force from Earth decreases rapidly following the inverse-square law $(F \propto 1/r^2)$.At some point between Earth and Mars,the gravitational pull from Earth and Mars will be equal and opposite,making the net force zero.After passing this point,the gravitational pull from Mars becomes dominant,and the net force increases until it reaches the weight on Mars,which is $W = m 	imes g_M = 60 	imes 4 = 240\, N$.Since the gravitational force follows an inverse-square law,the graph cannot be a straight line (ruling out $A$).Curve $C$ correctly shows the net force decreasing to zero at a point between the planets and then increasing as the passenger approaches Mars.

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