Suppose the earth stopped rotating. Then,the | vedclass

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(C) The effective weight $R$ of a body of mass $m$ at a latitude $\lambda$ on the rotating earth is given by $R = mg - m\omega^2 R_e \cos^2 \lambda$,w

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Increase at the equator

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(C) The effective weight $R$ of a body of mass $m$ at a latitude $\lambda$ on the rotating earth is given by $R = mg - m\omega^2 R_e \cos^2 \lambda$,where $\omega$ is the angular velocity of the earth and $R_e$ is the radius of the earth.At the equator,$\lambda = 0^\circ$,so $\cos \lambda = 1$. Thus,$R = mg - m\omega^2 R_e$.At the poles,$\lambda = 90^\circ$,so $\cos \lambda = 0$. Thus,$R = mg$.If the earth stops rotating,$\omega = 0$.At the poles,the weight remains $R = mg$ (no change).At the equator,the weight becomes $R = mg$,which is an increase compared to the rotating case $(mg - m\omega^2 R_e)$.Therefore,the weight of a body will increase at the equator.

Suppose the earth stopped rotating. Then,the weight of a body will

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