Supposing the energy of the fourth shell for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total energy $(E_n)$ of an electron in the $n^{th}$ shell is given by $E_n = \frac{E_1}{n^2}$,where $E_1$ is the energy of the ground state $(

Vedclass · Accepted Answer

$-800$

Vedclass · Answer

(C) The total energy $(E_n)$ of an electron in the $n^{th}$ shell is given by $E_n = \frac{E_1}{n^2}$,where $E_1$ is the energy of the ground state $(n=1)$.Given $E_4 = -25 \, a.u.$,we have $-25 = \frac{E_1}{4^2}$.Therefore,$E_1 = -25 	imes 16 = -400 \, a.u.$For a hydrogen-like atom,the potential energy $(PE)$ is related to the total energy $(E)$ by the relation $PE = 2 	imes E$.Thus,for the ground state $(n=1)$,$PE_1 = 2 	imes E_1 = 2 	imes (-400) = -800 \, a.u.$

Supposing the energy of the fourth shell for a hydrogen atom is $-25 \, a.u.$ (arbitrary unit). What would be its potential energy in the ground state?

Similar Questions

If the ionization energy of a hydrogen atom is $E$,then the ionization energy of $Li^{2+}$ will be ............ $E$.

In $He^{+}$ ion,the energy of $2^{nd}$ orbit is $-13.6 \ eV/atom$. The kinetic energy of the same orbit for $He^{+}$ ion will be:

$A$ bulb emits light of wavelength $4500 \ \mathring{A}$. The bulb is rated at $150 \ \text{W}$ and $8\%$ of the energy is emitted as light. How many photons are emitted by the bulb per second?

Which of the following is the radius of the first orbit of $He^{+}$ (in $pm$)?

The radii of the first,second,third,and fourth Bohr orbits of hydrogen are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module