Tangents to a circle at points $P$ and $Q$ on the circle intersect at a point $R$. If $PQ=6$ and $PR=5$,then the radius of the circle is

  • A
    $\frac{13}{3}$
  • B
    $4$
  • C
    $\frac{15}{4}$
  • D
    $\frac{16}{5}$

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