Ten men and $6$ women are to be seated in a row so that no two women sit together. The number of ways they can be seated is:

  • A
    $11! \times 10!$
  • B
    $\frac{11!}{6! 5!}$
  • C
    $\frac{10! 11!}{5!}$
  • D
    $\frac{11! 10!}{6!}$

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