The n^{th} term of an A.P. is given by T_n = | vedclass

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(D) Given the $n^{th}$ term of the $A.P.$ is $T_n = 4n + 3$.To find the first term $(a)$: Substitute $n = 1$,$a = T_1 = 4(1) + 3 = 7$.To find the $60^

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$7500$

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(D) Given the $n^{th}$ term of the $A.P.$ is $T_n = 4n + 3$.To find the first term $(a)$: Substitute $n = 1$,$a = T_1 = 4(1) + 3 = 7$.To find the $60^{th}$ term $(l)$: Substitute $n = 60$,$l = T_{60} = 4(60) + 3 = 240 + 3 = 243$.The sum of the first $n$ terms of an $A.P.$ is given by $S_n = \frac{n}{2}(a + l)$.For $n = 60$,$S_{60} = \frac{60}{2}(7 + 243)$.$S_{60} = 30(250) = 7500$.Therefore,the sum of the first $60$ terms is $7500$.

The $n^{th}$ term of an $A.P.$ is given by $T_n = 4n + 3$. Find the sum of the first $60$ terms of the $A.P.$

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