The P-V diagram of a system undergoing thermo | vedclass

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(D) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$. Here,$\Delta Q$ is the heat given to the system,$\Delta U$ is the c

Vedclass · Accepted Answer

$134$

Vedclass · Answer

(D) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$. Here,$\Delta Q$ is the heat given to the system,$\Delta U$ is the change in internal energy,and $\Delta W$ is the work done $BY$ the system. Given,heat given to the system $\Delta Q = 20 \ cal = 20 	imes 4.2 \ J = 84 \ J$. Work done $ON$ the system is $50 \ J$,which means work done $BY$ the system $\Delta W = -50 \ J$. Substituting these values into the equation: $84 \ J = \Delta U + (-50 \ J)$. Therefore,$\Delta U = 84 \ J + 50 \ J = 134 \ J$.

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