The pH values of (i) 0.1 M HCl_{(aq)},(ii) | vedclass

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Question

(A) The $pH$ values are determined as follows: $(i)$ $0.1 \ M \ HCl$ is a strong acid,so its $pH = -\log[H^+] = -\log(0.1) = 1$. (ii) $0.1 \ M \ KOH$

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$i < iii < iv < ii$

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(A) The $pH$ values are determined as follows: $(i)$ $0.1 \ M \ HCl$ is a strong acid,so its $pH = -\log[H^+] = -\log(0.1) = 1$. (ii) $0.1 \ M \ KOH$ is a strong base,so its $pOH = -\log[OH^-] = 1$,which means $pH = 14 - 1 = 13$. (iii) Tomato juice is acidic,typically having a $pH$ in the range of $4.0 - 4.5$. (iv) Pure water is neutral,having a $pH = 7.0$ at $25^{\circ}C$. Comparing these values: $1 (i) Therefore,the correct order is $i < iii < iv < ii$.

The $pH$ values of $(i) \ 0.1 \ M \ HCl_{(aq)}$,$(ii) \ 0.1 \ M \ KOH$,$(iii)$ tomato juice,and $(iv)$ pure water follow the order.

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