The HCF of two numbers is 9 and their product | vedclass

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(A) We know that for any two positive integers $a$ and $b$,the relationship between their $HCF$ and $LCM$ is given by: $	ext{HCF}(a, b) 	imes 	ext{

Vedclass · Accepted Answer

$32$

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(A) We know that for any two positive integers $a$ and $b$,the relationship between their $HCF$ and $LCM$ is given by: $	ext{HCF}(a, b) 	imes 	ext{LCM}(a, b) = a 	imes b$ Given: $	ext{HCF} = 9$ $	ext{Product of numbers} (a 	imes b) = 288$ Substituting the values in the formula: $9 	imes 	ext{LCM} = 288$ $	ext{LCM} = \frac{288}{9}$ $	ext{LCM} = 32$ Therefore,the $LCM$ of the two numbers is $32$.

The $HCF$ of two numbers is $9$ and their product is $288$. Find their $LCM$.

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