The $H-N-H$ bond angle in $NH_{3}$ molecule is

The sets of molecules in which the central atom has no lone pair of electrons are:
$i$. $SnCl_2, NH_3, SF_4$
$ii$. $HgCl_2, SO_3, SF_6$
$iii$. $BeCl_2, BF_3, PCl_5$
$iv$. $ClF_3, BrF_5, XeF_6$

How will you account for the $104.5^{\circ}$ bond angle in water?

Which of the following molecules is symmetrical?

Which of the following compounds have the same number of lone pairs on their central atom?
$I. XeF_5^- \quad II. BrF_3 \quad III. XeF_2 \quad IV. H_3S^{+} \quad V. CH_2$ (Methylene)

The bond angles $H-O-N$ and $O-N-O$ in the planar structure of nitric acid molecule are respectively: