The I.U.P.A.C. name of the following compound | vedclass

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(B) $1$. Identify the longest carbon chain. The longest chain contains $8$ carbon atoms,so the parent alkane is octane.$2$. Number the chain from the

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$5-$bromo-$3, 3, 6-$trimethyloctane

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(B) $1$. Identify the longest carbon chain. The longest chain contains $8$ carbon atoms,so the parent alkane is octane.$2$. Number the chain from the end that gives the substituents the lowest possible locants. Numbering from left to right gives substituents at positions $4, 3, 6, 6$. Numbering from right to left gives substituents at positions $3, 3, 6, 5$. Comparing the sets $(3, 3, 5, 6)$ and $(3, 4, 6, 6)$,the set $(3, 3, 5, 6)$ is lower.$3$. The substituents are: bromo at position $5$,and methyl groups at positions $3, 3, 6$.$4$. Combining these,the name is $5-$bromo$-3, 3, 6-$trimethyloctane.

The $I.U.P.A.C.$ name of the following compound is:

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