The P-V graph of an ideal gas cycle is shown | vedclass

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(C) In a $P-V$ diagram,the slope of an adiabatic process is given by $\frac{dP}{dV} = -\gamma \frac{P}{V}$,while the slope of an isothermal process is

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$BC$ and $DA$

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(C) In a $P-V$ diagram,the slope of an adiabatic process is given by $\frac{dP}{dV} = -\gamma \frac{P}{V}$,while the slope of an isothermal process is given by $\frac{dP}{dV} = -\frac{P}{V}$.Since $\gamma > 1$ for any ideal gas,the adiabatic curves are steeper than the isothermal curves.Looking at the graph,the segments $BC$ and $DA$ have a greater slope compared to the segments $AB$ and $CD$.Therefore,$BC$ and $DA$ represent the adiabatic processes,while $AB$ and $CD$ represent the isothermal processes.Thus,the correct option is $C$.

The $P-V$ graph of an ideal gas cycle is shown below. The adiabatic processes are described by:

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