The absolute configuration of the given molec | vedclass

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(D) To determine the absolute configuration,we assign priorities to the groups attached to each chiral carbon using the Cahn-Ingold-Prelog $(CIP)$ rul

Vedclass · Accepted Answer

$ (2S, 3R) $

Vedclass · Answer

(D) To determine the absolute configuration,we assign priorities to the groups attached to each chiral carbon using the Cahn-Ingold-Prelog $(CIP)$ rules.For the $C-2$ carbon:The groups are $-OH$ (priority $1$),$-CH(Cl)CH_3$ (priority $2$),$-CO_2H$ (priority $3$),and $-H$ (priority $4$).Since the lowest priority group $(-H)$ is on a horizontal bond,the configuration is reversed. The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise,which would be $R$,but due to the horizontal $-H$,it becomes $S$. Thus,$C-2$ is $2S$.For the $C-3$ carbon:The groups are $-Cl$ (priority $1$),$-CH(OH)CO_2H$ (priority $2$),$-CH_3$ (priority $3$),and $-H$ (priority $4$).Since the lowest priority group $(-H)$ is on a horizontal bond,the configuration is reversed. The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is counter-clockwise,which would be $S$,but due to the horizontal $-H$,it becomes $R$. Thus,$C-3$ is $3R$.Therefore,the absolute configuration is $(2S, 3R)$.

The absolute configuration of the given molecule is:

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