The acceleration due to gravity on the planet | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given that the acceleration due to gravity on planet $A$ is $9$ times that on planet $B$:$g_{A} = 9g_{B}$ $(i)$Using the third equation of motion,

Vedclass · Accepted Answer

$18 \,m$

Vedclass · Answer

(D) Given that the acceleration due to gravity on planet $A$ is $9$ times that on planet $B$:$g_{A} = 9g_{B}$ $(i)$Using the third equation of motion, $v^2 = u^2 + 2gh$. Since the initial velocity $u$ is the same for the jump on both planets and the final velocity $v$ at the maximum height is $0$, we have $u^2 = 2gh$, or $h = \frac{u^2}{2g}$.Since $u$ is constant for the same person,$h \propto \frac{1}{g}$Therefore, $\frac{h_{B}}{h_{A}} = \frac{g_{A}}{g_{B}}$Substituting the given values:$\frac{h_{B}}{2} = \frac{9g_{B}}{g_{B}} = 9$$h_{B} = 9 	imes 2 = 18 \,m$.

The acceleration due to gravity on the planet $A$ is $9$ times the acceleration due to gravity on planet $B$. $A$ man jumps to a height of $2 \,m$ on the surface of $A$. What is the height of jump by the same person on the planet $B$?

Similar Questions

$A$ body weighs $72 \ N$ on the surface of the earth. What is the gravitational force on it at a height equal to half the radius of the earth (in $N$)?

Suppose that the force of earth's gravity suddenly disappears,choose the correct answer out of the following statements.

As we move above the surface of the Earth,the value of acceleration due to gravity $g$ . . . . . . .

$A$ hole is drilled halfway to the center of the Earth. $A$ body weighs $300 \ N$ on the surface of the Earth. How much will it weigh at the bottom of the hole (in $N$)?

If the acceleration due to gravity at the Earth is $g$,the mass of the Earth is $80$ times that of the Moon,and the radius of the Earth is $4$ times that of the Moon,then the value of the acceleration due to gravity at the surface of the Moon will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module