The amount of iron (Fe) in g which can be pro | vedclass

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(C) The chemical formula of magnetite is $Fe_3O_4$.The molar mass of $Fe_3O_4 = (3 	imes 55.8) + (4 	imes 16) = 167.4 + 64 = 231.4 \ g/mol$.The numb

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$434$

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(C) The chemical formula of magnetite is $Fe_3O_4$.The molar mass of $Fe_3O_4 = (3 	imes 55.8) + (4 	imes 16) = 167.4 + 64 = 231.4 \ g/mol$.The number of moles in $600 \ g$ of $Fe_3O_4 = \frac{600}{231.4} \approx 2.593 \ mol$.According to the stoichiometry of the reaction $Fe_3O_4 + 4CO \longrightarrow 3Fe + 4CO_2$, $1 \ mol$ of $Fe_3O_4$ produces $3 \ mol$ of $Fe$.Therefore, $2.593 \ mol$ of $Fe_3O_4$ produces $2.593 	imes 3 = 7.779 \ mol$ of $Fe$.Mass of $Fe = 7.779 \ mol 	imes 55.8 \ g/mol \approx 434 \ g$.

The amount of iron $(Fe)$ in $g$ which can be produced from $600 \ g$ of magnetite ore is [Atomic mass of $Fe$ : $55.8$]

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