The angle between vector vec{Q} and the resul | vedclass

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(A) Let the two vectors be $\vec{A} = (2 \vec{Q} + 2 \vec{P})$ and $\vec{B} = (2 \vec{Q} - 2 \vec{P})$.The resultant vector $\vec{R}$ is the sum of th

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$0^{\circ}$

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(A) Let the two vectors be $\vec{A} = (2 \vec{Q} + 2 \vec{P})$ and $\vec{B} = (2 \vec{Q} - 2 \vec{P})$.The resultant vector $\vec{R}$ is the sum of these two vectors:$\vec{R} = \vec{A} + \vec{B} = (2 \vec{Q} + 2 \vec{P}) + (2 \vec{Q} - 2 \vec{P})$.Simplifying the expression:$\vec{R} = 2 \vec{Q} + 2 \vec{Q} + 2 \vec{P} - 2 \vec{P} = 4 \vec{Q}$.Since the resultant vector $\vec{R} = 4 \vec{Q}$ is a scalar multiple of $\vec{Q}$ with a positive constant $(4)$,the vector $\vec{R}$ points in the same direction as $\vec{Q}$.Therefore,the angle between vector $\vec{Q}$ and the resultant vector $\vec{R}$ is $0^{\circ}$.

The angle between vector $\vec{Q}$ and the resultant of $(2 \vec{Q} + 2 \vec{P})$ and $(2 \vec{Q} - 2 \vec{P})$ is:

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