The magnitude of the sum of two vectors vec{A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The resultant vector $\vec{R}$ of two vectors $\vec{A}$ and $\vec{B}$ is given by the vector addition rule: $\vec{R} = \vec{A} + \vec{B}$.The magn

Vedclass · Accepted Answer

$\sqrt{A^2 + B^2 + 2AB \cos 	heta}$

Vedclass · Answer

(A) The resultant vector $\vec{R}$ of two vectors $\vec{A}$ and $\vec{B}$ is given by the vector addition rule: $\vec{R} = \vec{A} + \vec{B}$.The magnitude of the resultant vector is calculated using the parallelogram law of vector addition.The formula for the magnitude $R$ is given by:$R = |\vec{A} + \vec{B}| = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$,where $A$ and $B$ are the magnitudes of vectors $\vec{A}$ and $\vec{B}$ respectively,and $	heta$ is the angle between them.

The magnitude of the sum of two vectors $\vec{A}$ and $\vec{B}$ with $\theta$ as the angle between them is:

Similar Questions

The angle between two forces of equal magnitude $R$,if the magnitude of their resultant is $\frac{R}{2}$,is:

If $\overrightarrow{A} = 3\widehat{i} + 2\widehat{j}$ and $\overrightarrow{B} = \widehat{i} + \widehat{j} - 2\widehat{k}$,find their sum using the algebraic method.

While travelling from one station to another,a car travels $75 \, km$ North,$60 \, km$ North-east,and $20 \, km$ East. The minimum distance between the two stations is.......$km$

Three vectors each of magnitude $3 \sqrt{1.5}$ units are acting at a point. If the angle between any two vectors is $\frac{\pi}{3}$,then the magnitude of the resultant vector of the three vectors is

Two forces whose magnitudes are in the ratio $5:3$ are acting at a point at an angle $60^{\circ}$ simultaneously. If the resultant of the two forces is $35 \ N$,then the magnitudes of the two forces respectively are

Vedclass Test Series

Exam Paper Generator

Online Exam Module