The angular resolution of a 10 ;cm diameter t | vedclass

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(D) The angular resolution of a telescope is given by the formula: $d	heta = \frac{1.22 \lambda}{D}$.Here,the wavelength $\lambda = 5000 \;\mathring

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$10^{-6} \;rad$

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(D) The angular resolution of a telescope is given by the formula: $d	heta = \frac{1.22 \lambda}{D}$.Here,the wavelength $\lambda = 5000 \;\mathring A = 5000 	imes 10^{-10} \;m = 5 	imes 10^{-7} \;m$.The diameter of the telescope aperture $D = 10 \;cm = 0.1 \;m = 10^{-1} \;m$.Substituting these values into the formula:$d	heta = \frac{1.22 	imes 5 	imes 10^{-7}}{10^{-1}}$$d	heta = 1.22 	imes 5 	imes 10^{-6}$$d	heta = 6.1 	imes 10^{-6} \;rad$.This value is of the order of $10^{-6} \;rad$.

The angular resolution of a $10 \;cm$ diameter telescope at a wavelength of $5000 \;\mathring A$ is of the order of:

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