The area in square units of the region bounded by the curve $y = \sqrt{16 - x^2}$ and the lines $x = 0, x = 4$ above the $X$-axis is: (in $\pi$)

The area of the region (in sq. units) enclosed by the curve $y=x^3-19x+30$ and the $x$-axis is

The slope of the tangent to a curve $y = f(x)$ at $(x, f(x))$ is $2x + 1$. If the curve passes through the point $(1, 2)$,then the area of the region bounded by the curve,the $x$-axis,and the line $x = 1$ is:

The area of the region enclosed by the curve $f(x) = \max \{\sin x, \cos x\}$,$-\pi \leq x \leq \pi$ and the $x$-axis is

The area of the smaller part between the circle $x^2+y^2=4$ and the line $x=1$ is . . . . . . sq. units.

The area of the circle $x^{2}+y^{2}=16$ exterior to the parabola $y^{2}=6x$ is