The area of a quadrilateral is 420 , m^{2} an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The area of a quadrilateral can be calculated using the formula: $	ext{Area} = \frac{1}{2} 	imes d 	imes (p_{1} + p_{2})$,where $d$ is the leng

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(C) The area of a quadrilateral can be calculated using the formula: $	ext{Area} = \frac{1}{2} 	imes d 	imes (p_{1} + p_{2})$,where $d$ is the length of the diagonal and $p_{1}, p_{2}$ are the lengths of the perpendiculars from the opposite vertices to the diagonal.Given: $	ext{Area} = 420 \, m^{2}$,$p_{1} = 18 \, m$,and $p_{2} = 12 \, m$.Substituting the values into the formula:$420 = \frac{1}{2} 	imes d 	imes (18 + 12)$$420 = \frac{1}{2} 	imes d 	imes 30$$420 = 15 	imes d$$d = \frac{420}{15}$$d = 28 \, m$.Thus,the length of the diagonal is $28 \, m$.

The area of a quadrilateral is $420 \, m^{2}$ and the perpendiculars drawn to one diagonal from the opposite vertices are $18 \, m$ and $12 \, m$. Then,the length of the diagonal is......$m$

Similar Questions

The least number of square slabs that can be fitted in a room of $10.5 \text{ m}$ long and $3 \text{ m}$ wide is........?

The length of a rectangular hall is $\frac{4}{3}$ of its width. If the area of the hall is $300 \, m^2$,what is the difference between the length and the breadth? (in $m$)

The perimeter of a right triangle is $12 \, cm$. The hypotenuse is $5 \, cm$. What are the other two sides and the area of the triangle?

How many tiles,each $4 \, dm$ square,will be required to cover the floor of a room $8 \, m$ long and $6 \, m$ broad?

The perimeter of a right-angled triangle is $90\, cm$ and its hypotenuse is $39\, cm$. Find its other sides.

Vedclass Test Series

Exam Paper Generator

Online Exam Module