The area of the parallelogram,whose diagonals are $\vec{d}_1 = 2 \hat{i} - \hat{j} + \hat{k}$ and $\vec{d}_2 = \hat{i} + 3 \hat{j} - \hat{k}$,is equal to

  • A
    $\frac{\sqrt{26}}{2}$ square units
  • B
    $\frac{2}{\sqrt{26}}$ square units
  • C
    $\frac{\sqrt{62}}{2}$ square units
  • D
    $\frac{2}{\sqrt{62}}$ square units

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