The atmospheric pressure at a place is 10^5 , | vedclass

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(A) The atmospheric pressure is given by $P = h ho g$.Standard atmospheric pressure is $P = 1.013 	imes 10^5 \,Pa \approx 10^5 \,Pa$.This pressure

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$3$

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(A) The atmospheric pressure is given by $P = h ho g$.Standard atmospheric pressure is $P = 1.013 	imes 10^5 \,Pa \approx 10^5 \,Pa$.This pressure is equivalent to a mercury column of height $h_{Hg} = 0.76 \,m$ with density $ho_{Hg} = 13600 \,kg/m^3$.For the barometric liquid (tribromomethane),the density is $ho_{TBM} = 2.9 	imes 1000 \,kg/m^3 = 2900 \,kg/m^3$.Using the principle $P = h_{Hg} ho_{Hg} g = h_{TBM} ho_{TBM} g$,we have:$h_{TBM} = \frac{h_{Hg} ho_{Hg}}{ho_{TBM}}$$h_{TBM} = \frac{0.76 	imes 13600}{2900} \approx 3.56 \,m$.Given the approximation $10^5 \,Pa$ and standard values,the calculated height is approximately $3.52 \,m$.

The atmospheric pressure at a place is $10^5 \,Pa$. If tribromomethane (specific gravity $= 2.9$) is employed as the barometric liquid,the barometric height is .......... $m$. (in $.52$)

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