The atomic number of an element is 35 and its | vedclass

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(A) The atomic number of the element is $Z = 35$,which corresponds to Bromine $(Br)$.The electronic configuration of Bromine is $1s^2 \, 2s^2 \, 2p^6

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$7$

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(A) The atomic number of the element is $Z = 35$,which corresponds to Bromine $(Br)$.The electronic configuration of Bromine is $1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 3d^{10} \, 4s^2 \, 4p^5$ or $[Ar] \, 3d^{10} \, 4s^2 \, 4p^5$.The outermost shell is the $n = 4$ shell.The number of electrons in the $4s$ and $4p$ orbitals is $2 + 5 = 7$.Therefore,the number of electrons in the outermost shell is $7$.

The atomic number of an element is $35$ and its mass number is $81$. The number of electrons in the outermost shell is:

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