What is the lowest value of $n$ that allows $g$ orbitals to exist?

  • A
    $n = 3$
  • B
    $n = 4$
  • C
    $n = 5$
  • D
    $n = 6$

Explore More

Similar Questions

The number of unpaired electrons in $1s^2 2s^2 2p^3$ is:

For a hydrogen atom,the orbital$(s)$ with the lowest energy is/are:
$A$. $4s$
$B$. $3p_x$
$C$. $3d_{x^2-y^2}$
$D$. $3d_{z^2}$
$E$. $4p_z$
Choose the correct answer from the options given below:

Which of the following sets of quantum numbers is not possible?

Which of the following represents the correct order of energy for the orbitals?

Difficult
View Solution

The atomic number of an element is $35$. What is the total number of electrons present in all the $p-$ orbitals of the ground state atom of that element?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo