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(C) The acceleration of a particle performing $SHM$ is given by $a = -\omega^{2} x$,where $x = A \sin(\omega t + \phi)$.To find the average accelerati

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zero

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(C) The acceleration of a particle performing $SHM$ is given by $a = -\omega^{2} x$,where $x = A \sin(\omega t + \phi)$.To find the average acceleration over one complete oscillation (time period $T$),we integrate the acceleration over the interval $[0, T]$ and divide by $T$.$	ext{Average acceleration} = \frac{1}{T} \int_{0}^{T} a(t) dt = \frac{1}{T} \int_{0}^{T} -\omega^{2} A \sin(\omega t + \phi) dt$.Since the integral of a sine function over one full period is zero,the average acceleration is $0$.

The average acceleration of a particle performing $SHM$ over one complete oscillation is:

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