The average atomic mass of a sample of an ele | vedclass

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(C) Let the percentage of isotope $_8^{18}X$ be $y \%$. Then,the percentage of isotope $_8^{16}X$ is $(100 - y) \%$.The average atomic mass is given b

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(C) Let the percentage of isotope $_8^{18}X$ be $y \%$. Then,the percentage of isotope $_8^{16}X$ is $(100 - y) \%$.The average atomic mass is given by the formula:$	ext{Average atomic mass} = \frac{(16 	imes (100 - y)) + (18 	imes y)}{100} = 16.2$Multiplying by $100$ on both sides:$1600 - 16y + 18y = 1620$Simplifying the equation:$2y = 1620 - 1600$$2y = 20$$y = 10$Thus,the percentage of isotope $_8^{18}X$ is $10 \%$ and the percentage of isotope $_8^{16}X$ is $(100 - 10) \% = 90 \%$.

The average atomic mass of a sample of an element $X$ is $16.2 \, u$. What are the percentages of isotopes $_8^{16}X$ and $_8^{18}X$ in the sample (in $\%$)?

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