The average weight of three boys A, B and C i | vedclass

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(D) The sum of weights of $A, B$ and $C$ is $3 	imes 54 \frac{1}{3} = 3 	imes \frac{163}{3} = 163 \, kg.$The sum of weights of $B, D$ and $E$ is $3

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(D) The sum of weights of $A, B$ and $C$ is $3 	imes 54 \frac{1}{3} = 3 	imes \frac{163}{3} = 163 \, kg.$The sum of weights of $B, D$ and $E$ is $3 	imes 53 = 159 \, kg.$Adding these two sums gives $(A + B + C) + (B + D + E) = 163 + 159 = 322 \, kg.$This simplifies to $A + 2B + C + D + E = 322 \, kg.$To find the average of $A, B, C, D$ and $E$,we need the sum $(A + B + C + D + E)$.Since the value of $B$ is unknown,we cannot determine the total sum $(A + B + C + D + E) = 322 - B$.Therefore,the average weight cannot be calculated with the given information.

The average weight of three boys $A, B$ and $C$ is $54 \frac{1}{3} \, kg,$ while the average weight of three boys $B, D$ and $E$ is $53 \, kg.$ What is the average weight of $A, B, C, D$ and $E$ (in $kg$)?

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