The beats are produced when there is a superposition of two sound waves which have:

$A$ tuning fork of frequency $n$ produces $x$ beats per second when sounded with a vibrating sonometer string. What must have been the frequency of the string, when a slight increase in tension produces lesser beats per second than before?

The velocity of sound in a gas,in which two wavelengths $4.08\,m$ and $4.16\,m$ produce $40$ beats in $12\,s$,will be ..............$m\,s^{-1}$.

$A$ string under a tension of $129.6 \ N$ produces $10 \ beats/s$ when it is vibrated along with a tuning fork. When the tension in the string is increased to $160 \ N$,it sounds in unison with the same tuning fork. Calculate the fundamental frequency of the tuning fork in $Hz$.

Two identical straight wires are stretched so as to produce $6$ beats per second when vibrating simultaneously with tensions $T_1$ and $T_2$ respectively. On changing the tension slightly in one of them,the beat frequency remains unchanged. This will happen when (Given $\rightarrow T_1 > T_2$)

The fundamental frequency '$n$' of a tuning fork is $288$ Hz. It will not resonate with which of the following frequencies (in $Hz$)?