The bond angle H-X-H is the greatest in the c | vedclass

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(B) The bond angle depends on the hybridization of the central atom and the repulsion between lone pairs and bond pairs. In $CH_4$,the central atom $C

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$CH_4$

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(B) The bond angle depends on the hybridization of the central atom and the repulsion between lone pairs and bond pairs. In $CH_4$,the central atom $C$ is $sp^3$ hybridized with no lone pair,resulting in a tetrahedral geometry with a bond angle of $109.5^{\circ}$. In $NH_3$,$H_2O$,and $PH_3$,the central atoms have lone pairs which cause bond pair-lone pair repulsion,leading to a decrease in bond angle from the ideal tetrahedral angle. Specifically,$PH_3$ has a bond angle of approximately $93.5^{\circ}$ due to the lack of hybridization and the large size of the $P$ atom. Therefore,$CH_4$ has the greatest bond angle among the given options.

List-$I$ (molecules/ions)	List-$II$ (No. of lone pairs of $e^-$ on central atom)
$A$. $IF_7$	$I$. Three
$B$. $ICl_4^-$	$II$. One
$C$. $XeF_6$	$III$. Two
$D$. $XeF_2$	$IV$. Zero

The bond angle $H-X-H$ is the greatest in the compound

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ (molecules/ions) List-$II$ (No. of lone pairs of $e^-$ on central atom)

$A$. $IF_7$ $I$. Three

$B$. $ICl_4^-$ $II$. One

$C$. $XeF_6$ $III$. Two

$D$. $XeF_2$ $IV$. Zero

Choose the correct answer from the options given below:

In carbon tetrachloride,the four valencies of carbon are directed towards the four corners of a:

The shape of the $XeF_2$ molecule is ..........

Which of the following is $NOT$ tetrahedral in shape?

Which of the following is isoelectronic as well as has same structure as that of $N_2O$?

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