The bond dissociation energy (E) and bond len | vedclass

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Question

(C) Bond dissociation energy $(E)$ is directly proportional to the bond order,while bond length $(R)$ is inversely proportional to the bond order.The

Vedclass · Accepted Answer

$E(N_2) > E(O_2) > E(F_2)$ and $R(F_2) > R(O_2) > R(N_2)$

Vedclass · Answer

(C) Bond dissociation energy $(E)$ is directly proportional to the bond order,while bond length $(R)$ is inversely proportional to the bond order.The bond orders are: $N_2$ (triple bond,$B.O. = 3$),$O_2$ (double bond,$B.O. = 2$),and $F_2$ (single bond,$B.O. = 1$).Therefore,the order of bond dissociation energy is: $E(N_2) > E(O_2) > E(F_2)$.The order of bond length is: $R(F_2) > R(O_2) > R(N_2)$.

The bond dissociation energy $(E)$ and bond length $(R)$ of $O_2$,$N_2$,and $F_2$ follow the order as:

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