The number of nodal planes present in $\sigma^{*}s$ antibonding orbitals is

Why do $N_2$,$NO^+$,$CN^-$,and $CO$ have the same bond order?

For $F_2$ and $OF$ molecules,consider the following statements:
$(a)$ Bond order for both is one
$(b)$ $OF$ is paramagnetic but $F_2$ is diamagnetic
$(c)$ $F_2$ is more likely to dissociate into atoms than $OF$
$(d)$ Both have greater number of electrons in $BMO$ than that in $ABMO$
Which of the following statements are true $(T)$ or false $(F)$ respectively?

The total number of antibonding molecular orbitals,formed from $2s$ and $2p$ atomic orbitals in a diatomic molecule is . . . . . .

Assuming that Hund's rule is violated,the bond order and magnetic nature of the diatomic molecule $B_2$ is

Which of the following is diamagnetic?