The bond order values of anions of sodium per | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Sodium peroxide $(Na_2O_2)$ contains the peroxide anion $O_2^{2-}$.Potassium superoxide $(KO_2)$ contains the superoxide anion $O_2^-$.For $O_2^{2

Vedclass · Accepted Answer

$1, 1.5$

Vedclass · Answer

(A) Sodium peroxide $(Na_2O_2)$ contains the peroxide anion $O_2^{2-}$.Potassium superoxide $(KO_2)$ contains the superoxide anion $O_2^-$.For $O_2^{2-}$: Total electrons = $18$. Electronic configuration: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$.Bond order = $\frac{10 - 8}{2} = 1$.For $O_2^-$: Total electrons = $17$. Electronic configuration: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^1$.Bond order = $\frac{10 - 7}{2} = 1.5$.

The bond order values of anions of sodium peroxide and potassium superoxide are respectively:

Similar Questions

Select the correct order $-$

Among $H_2, He_2^{+}, Li_2, Be_2, B_2, C_2, N_2, O_2^{-}$,and $F_2$,the number of diamagnetic species is (Atomic numbers: $H=1, He=2, Li=3, Be=4, B=5, C=6, N=7, O=8, F=9$)

The bond order of $CO$ molecule is

The incorrect statement regarding molecular orbital $(s)$ is

What is the number of electrons present in antibonding orbitals of $N_2$ molecule according to molecular orbital theory?

Vedclass Test Series

Exam Paper Generator

Online Exam Module