The Boolean expression for the given combinat | vedclass

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(D) $1$. The circuit consists of an $AND$ gate, a $NOT$ gate, and an $OR$ gate.$2$. The inputs $A$ and $B$ are fed into an $AND$ gate. The output of t

Vedclass · Accepted Answer

$Y = (A \cdot B) + \bar{C}$

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(D) $1$. The circuit consists of an $AND$ gate, a $NOT$ gate, and an $OR$ gate.$2$. The inputs $A$ and $B$ are fed into an $AND$ gate. The output of the $AND$ gate is $A \cdot B$.$3$. The input $C$ is fed into a $NOT$ gate. The output of the $NOT$ gate is $\bar{C}$.$4$. The outputs of the $AND$ gate $(A \cdot B)$ and the $NOT$ gate $(\bar{C})$ are fed into an $OR$ gate.$5$. The final output $Y$ of the $OR$ gate is the sum of its inputs: $Y = (A \cdot B) + \bar{C}$.

Input $A$	Input $B$	Output $Y$
$0$	$1$	$C$
$0$	$0$	$D$
$1$	$0$	$E$
$1$	$1$	$F$

The Boolean expression for the given combination of logic gates is

Similar Questions

The truth table given below is for which gate?
$A: 0, 0, 1, 1$
$B: 0, 1, 0, 1$
$C: 1, 1, 1, 0$

The output $Y$ for the inputs $A$ and $B$ of the circuit is given by the truth table of the shown circuit:

Identify the correct truth table of the given logical circuit.

For a $NAND$ gate, the inputs and outputs are given in the table below. The values taken by $C, D, E, F$ are respectively:
Input $A$ Input $B$ Output $Y$
$0$ $1$ $C$
$0$ $0$ $D$
$1$ $0$ $E$
$1$ $1$ $F$

The Boolean expression for the following combination is

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