The chances to fail in Physics are 20 % and t | vedclass

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(A) Let $P(A)$ be the probability of failing in Physics and $P(B)$ be the probability of failing in Mathematics. Given $P(A) = \frac{20}{100} = 0.2$ a

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(A) Let $P(A)$ be the probability of failing in Physics and $P(B)$ be the probability of failing in Mathematics. Given $P(A) = \frac{20}{100} = 0.2$ and $P(B) = \frac{10}{100} = 0.1$. Assuming the events are independent,the probability of failing in at least one subject is given by $P(A \cup B) = P(A) + P(B) - P(A \cap B)$. Since the events are independent,$P(A \cap B) = P(A) \cdot P(B) = 0.2 	imes 0.1 = 0.02$. Therefore,$P(A \cup B) = 0.2 + 0.1 - 0.02 = 0.28$. Converting to percentage,$0.28 	imes 100 = 28 \%$.

The chances to fail in Physics are $20 \%$ and the chances to fail in Mathematics are $10 \%$. What are the chances to fail in at least one subject (in $\%$)?

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