The change in the internal energy of 3 moles | vedclass

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(B) The change in internal energy $(\Delta U)$ for a gas at constant volume is given by the formula:$\Delta U = n C_V \Delta T$Where:$n = 3 	ext{ mol

Vedclass · Accepted Answer

$18$

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(B) The change in internal energy $(\Delta U)$ for a gas at constant volume is given by the formula:$\Delta U = n C_V \Delta T$Where:$n = 3 	ext{ moles}$$\Delta U = 1080 \ J$$\Delta T = 40^{\circ}C - 20^{\circ}C = 20 \ K$Rearranging the formula to solve for $C_V$:$C_V = \frac{\Delta U}{n \Delta T}$Substituting the given values:$C_V = \frac{1080}{3 	imes 20}$$C_V = \frac{1080}{60}$$C_V = 18 \ J \ mol^{-1} \ K^{-1}$Thus, the molar specific heat at constant volume is $18 \ J \ mol^{-1} \ K^{-1}$.

Column-$I$	Column-$II$
$(a)$ Horizontal line parallel to $V$-axis	$(i)$ Adiabatic process
$(b)$ Vertical line parallel to $P$-axis	$(ii)$ Isobaric process
	$(iii)$ Isochoric process

The change in the internal energy of $3$ moles of a gas heated at constant volume from $20^{\circ}C$ to $40^{\circ}C$ is $1080 \ J$. The molar specific heat of the gas at constant volume in $J \ mol^{-1} \ K^{-1}$ is:

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