(D) The area of the triangle $AOB$ in the $V-q$ graph is given by:Area $= \frac{1}{2} \times \text{base} \times \text{height}$Area $= \frac{1}{2} \tim

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(D) The area of the triangle $AOB$ in the $V-q$ graph is given by:Area $= \frac{1}{2} \times \text{base} \times \text{height}$Area $= \frac{1}{2} \times q \times V$We know that the energy stored in a capacitor is given by $U = \frac{1}{2} qV$.Therefore,the area of the triangle $AOB$ is equal to the energy stored by the capacitor.Thus,the area is proportional to the energy stored by the capacitor.

Class 12 Physics Electric Potential and Capacitance Energy Stored in a Capacitor

Medium

The charge $q$ on a capacitor varies with voltage $V$ as shown in the figure. The area of the triangle $AOB$ is proportional to

A
electric field between the plates
B
electric flux between the plates
C
energy density
D
energy stored by the capacitor

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Class 12 Questions

Class 12

Physics Questions

Chapter

Electric Potential and Capacitance

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Energy Stored in a Capacitor

The amount of work done in increasing the voltage across the plates of a capacitor from $5 V$ to $10 V$ is $W$. The work done in increasing it from $10 V$ to $15 V$ will be

MediumMHT CET 2016

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If the potential of a capacitor having capacity of $6\,\mu F$ is increased from $10\,V$ to $20\,V$,then the increase in its energy will be:

Medium

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Two capacitors,each of value $10 \ \mu F$,are connected in parallel and charged to $200 \ V \ DC$. What is the energy stored in the combination in Joules?

Easy

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If the charge on a capacitor is increased by $2 \ C$, the energy stored in it increases by $21 \%$. The original charge on the capacitor is (in $C$)

DifficultWBJEE 2009

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The capacitance of a capacitor is $4 \times 10^{-6} \ F$ and it is charged to a potential difference of $100 \ V$. The energy required to completely discharge it is . . . . . . $J$.

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The charge $q$ on a capacitor varies with voltage $V$ as shown in the figure. The area of the triangle $AOB$ is proportional to

Similar Questions

The amount of work done in increasing the voltage across the plates of a capacitor from $5 V$ to $10 V$ is $W$. The work done in increasing it from $10 V$ to $15 V$ will be

If the potential of a capacitor having capacity of $6\,\mu F$ is increased from $10\,V$ to $20\,V$,then the increase in its energy will be:

Two capacitors,each of value $10 \ \mu F$,are connected in parallel and charged to $200 \ V \ DC$. What is the energy stored in the combination in Joules?

If the charge on a capacitor is increased by $2 \ C$, the energy stored in it increases by $21 \%$. The original charge on the capacitor is (in $C$)

The capacitance of a capacitor is $4 \times 10^{-6} \ F$ and it is charged to a potential difference of $100 \ V$. The energy required to completely discharge it is . . . . . . $J$.

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