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(B) The potential difference across the capacitor at $t = 0$ is given by $V = \frac{q}{C}$.Given $q = 30\, \mu C$ and $C = 3\, \mu F$,we have $V = \fr

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$2$

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(B) The potential difference across the capacitor at $t = 0$ is given by $V = \frac{q}{C}$.Given $q = 30\, \mu C$ and $C = 3\, \mu F$,we have $V = \frac{30\, \mu C}{3\, \mu F} = 10\, V$.When the key is closed,the capacitor discharges through the resistor $R = 5\, M\Omega = 5 	imes 10^6\, \Omega$.The initial current $i_0$ flowing through the circuit at $t = 0$ is given by $i_0 = \frac{V}{R}$.Substituting the values,$i_0 = \frac{10\, V}{5 	imes 10^6\, \Omega} = 2 	imes 10^{-6}\, A$.Since $1\, \mu A = 10^{-6}\, A$,the current $i_0 = 2\, \mu A$.Thus,the value of $'x'$ is $2$.

The circuit shown in the figure consists of a charged capacitor of capacity $3\, \mu F$ and a charge of $30\, \mu C$. At time $t = 0,$ when the key is closed,the value of current flowing through the $5\, M\Omega$ resistor is $'x'\, \mu A$. The value of $'x'$ to the nearest integer is .........

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