The Clemmensen reduction of acetone yields

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Question

(C) The Clemmensen reduction involves the reduction of carbonyl groups $(C=O)$ to methylene groups $(CH_2)$ using zinc amalgam $(Zn(Hg))$ and concentr

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Propane

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(C) The Clemmensen reduction involves the reduction of carbonyl groups $(C=O)$ to methylene groups $(CH_2)$ using zinc amalgam $(Zn(Hg))$ and concentrated hydrochloric acid $(HCl)$. Acetone is $CH_3COCH_3$. When acetone undergoes Clemmensen reduction,the carbonyl group is reduced to a methylene group: $CH_3COCH_3 + 4[H] \xrightarrow{Zn(Hg)/HCl} CH_3CH_2CH_3 + H_2O$. The product formed is propane.

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