The coordinates of the point which divides th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the points be $A(2, -1, 3)$ and $B(4, 3, 1)$. The ratio is $m_1 : m_2 = 3 : 4$.Using the section formula for internal division:$x = \frac{m_1

Vedclass · Accepted Answer

$(\frac{20}{7}, \frac{5}{7}, \frac{15}{7})$

Vedclass · Answer

(D) Let the points be $A(2, -1, 3)$ and $B(4, 3, 1)$. The ratio is $m_1 : m_2 = 3 : 4$.Using the section formula for internal division:$x = \frac{m_1 x_2 + m_2 x_1}{m_1 + m_2} = \frac{3(4) + 4(2)}{3 + 4} = \frac{12 + 8}{7} = \frac{20}{7}$$y = \frac{m_1 y_2 + m_2 y_1}{m_1 + m_2} = \frac{3(3) + 4(-1)}{3 + 4} = \frac{9 - 4}{7} = \frac{5}{7}$$z = \frac{m_1 z_2 + m_2 z_1}{m_1 + m_2} = \frac{3(1) + 4(3)}{3 + 4} = \frac{3 + 12}{7} = \frac{15}{7}$Thus,the coordinates are $(\frac{20}{7}, \frac{5}{7}, \frac{15}{7})$.Therefore,the correct option is $D$.

The coordinates of the point which divides the line segment joining the points $(2, -1, 3)$ and $(4, 3, 1)$ in the ratio $3 : 4$ internally are given by:

Similar Questions

If $A(4,3,5)$,$B(0,-2,2)$,and $C(3,2,1)$ are three points,then the coordinates of the point $D$ where the bisector of $\angle BAC$ meets the side $BC$ are:

If the points $A(-1,0,7), B(3,2, t), C(5, k,-2)$ are collinear, then the ratio in which the point $P(t, k-2t, t+k)$ divides the line segment $BC$ is

The ratio in which the point $P$,whose abscissa is $3$,divides the line segment joining $A(6, 5)$ and $B(-1, 4)$ is equal to .........

If $A(1, 2, -1)$ and $B(-1, 0, 1)$ are given,then the coordinates of point $P$ which divides the line segment $AB$ externally in the ratio $1:2$ are:

If the point $(a, 8, -2)$ divides the line segment joining the points $(1, 4, 6)$ and $(5, 2, 10)$ in the ratio $m: n$,then $\frac{2m}{n} - \frac{a}{3} =$

Vedclass Test Series

Exam Paper Generator

Online Exam Module