The coagulating power of electrolytes having | vedclass

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(B) $As_{2}S_{3}$ is a negatively charged sol. According to the Hardy-Schulze rule, the coagulating power of an electrolyte depends on the valency of

Vedclass · Accepted Answer

$Na^{+} < Ba^{2+} < Al^{3+}$

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(B) $As_{2}S_{3}$ is a negatively charged sol. According to the Hardy-Schulze rule, the coagulating power of an electrolyte depends on the valency of the active ion (the ion carrying a charge opposite to that of the colloidal particles). For a negatively charged sol, the coagulating power increases with the increase in the magnitude of the positive charge on the cation. The charges on the given ions are: $Na^{+}$ $(+1)$, $Ba^{2+}$ $(+2)$, and $Al^{3+}$ $(+3)$. Therefore, the order of coagulating power is $Na^{+} < Ba^{2+} < Al^{3+}$.

The coagulating power of electrolytes having ions $Na^{+}$, $Al^{3+}$, and $Ba^{2+}$ for $As_{2}S_{3}$ sol increases in the order

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