The complex ion [Fe(CN)_6]^{4-} contains | vedclass

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Question

(D) In $[Fe(CN)_6]^{4-}$,the oxidation state of $Fe$ is $+2$. The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$. Since $CN^-$ is a strong field

Vedclass · Accepted Answer

six sigma bonds

Vedclass · Answer

(D) In $[Fe(CN)_6]^{4-}$,the oxidation state of $Fe$ is $+2$. The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$. Since $CN^-$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbitals. This results in $d^2sp^3$ hybridization,which corresponds to an octahedral geometry. There are $6$ $Fe-C$ sigma bonds formed by the donation of electron pairs from $6$ $CN^-$ ligands. The total number of electrons on $Fe^{2+}$ is $26 - 2 = 24$. Thus,the statement regarding $6$ sigma bonds is correct.

The complex ion $[Fe(CN)_6]^{4-}$ contains

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